Table 40
Increase in Proportion of Residents With No Health Insurance, 1987-97
Rank	State	Amt.		Rank	State	Amt.
1	New Jersey	108.9%		27	Mississippi	17.5%
2	Massachusetts	100.0%		28	New Hampshire	16.8%
3	North Dakota	97.4%		29	North Carolina	16.5%
4	Connecticut	87.5%		30	Texas	16.1%
5	Maine	77.4%		31	Idaho	15.7%
6	Iowa	64.4%		32	Kansas	13.6%
7	South Carolina	51.4%		33	Florida	12.6%
8	NEW YORK	50.9%		34	Nebraska	12.5%
9	Rhode Island	50.0%		35	Alaska	11.7%
10	Pennsylvania	40.3%		36	Nevada	10.1%
11	Minnesota	39.4%		37	Colorado	9.4%
12	Michigan	38.1%		38	Utah	8.1%
13	Maryland	36.7%		39	Hawaii	0.0%
14	Wyoming	36.0%		40	New Mexico	-0.4%
15	Georgia	35.4%		41	Kentucky	-1.3%
16	Arizona	33.2%		42	Oklahoma	-1.7%
17	California	28.0%		43	Alabama	-1.9%
18	Illinois	27.8%		44	Vermont	-3.1%
19	West Virginia	27.4%		45	Tennessee	-6.2%
20	Montana	25.8%		46	Oregon	-11.3%
21	Ohio	25.0%		47	Washington	-12.3%
22	Delaware	24.8%		48	Louisiana	-12.9%
23	Wisconsin	23.1%		49	South Dakota	-13.9%
24	Virginia	21.2%		50	Indiana	-14.9%
25	Missouri	20.0%		U.S. average		24.8%
26	Arkansas	17.9%		N.Y.S. % above		105.2%
Source: U.S. Census Bureau
In 1987, and into the mid-1990s, New York's proportion of uninsured residents was lower than the national average.